find the angular speed of revolution of Earth required so that the body on its surface at equater would feel no weight
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Explanation:
The angular speed of earth is rad s-1, so that the object on equator may appear weightless, is (radius of earth = 6400 km) ∴ω=√gR=√9.86400×103=1.23×10-3rad s-1.
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Given:
the body on its surface at equator would feel no weight
To Find:
the angular speed of revolution of Earth required
Explanation:
mg = mrw²
w² = g/r
w = √g/r
R = 6400km
= 6.4 × 10⁻⁶m
w = √(10/6.4 ×10⁻⁶ )
= 1.25 × 10⁻³ rad/s
Answer = 1.25 × 10⁻³ rad/s
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