Find the angular velocity of a satellite which revolves in a circular orbit of radius 35000 km and completes one round in 12 hours
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24
Given Conditions ⇒
Radius of the circular orbit = 35,000 km.
Time taken to complete one round = 12 hours.
Angle subtended at the centre = 360° [ ∵ Earth is approx circular].
∵ 360° = 2π rad.
∴ Angle subtended at the centre = 2π
Now, Using the Formula,
Angular Velocity (ω) = Angle subtended at the centre in radians/Time taken to complete 1 round.
∴ ω = 2π/12
⇒ ω =(44/7) ÷ 12
⇒ ω = 0.524 rad/hr.
∴ Angular velocity of the satellite is 0.524 rad/hr.
Hope it helps.
Answered by
2
Answer:
Angular velocity ( W ) :
the rate of change of angular position of a rotating body
W = angular distance / Timer period
angular distance = R× angle converd = 3500×10^3 × 2π
W = 3500 × 10^3 × 2π / 12 × 60 ×60
= 508.79 radian / sec
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