Find the angular velocity of a satellite which revolves in a circular orbit of radius 35000 km and completes one round in 12 hours.
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Answered by
69
Given Conditions ⇒
Radius of the circular orbit = 35,000 km.
Time taken to complete one round = 12 hours.
Angle subtended at the centre = 360° [ ∵ Earth is approx circular].
∵ 360° = 2π rad.
∴ Angle subtended at the centre = 2π
Now, Using the Formula,
Angular Velocity (ω) = Angle subtended at the centre in radians/Time taken to complete 1 round.
∴ ω = 2π/12
⇒ ω =(44/7) ÷ 12
⇒ ω = 0.524 rad/hr.
∴ Angular velocity of the satellite is 0.524 rad/hr.
Hope it helps.
Radius of the circular orbit = 35,000 km.
Time taken to complete one round = 12 hours.
Angle subtended at the centre = 360° [ ∵ Earth is approx circular].
∵ 360° = 2π rad.
∴ Angle subtended at the centre = 2π
Now, Using the Formula,
Angular Velocity (ω) = Angle subtended at the centre in radians/Time taken to complete 1 round.
∴ ω = 2π/12
⇒ ω =(44/7) ÷ 12
⇒ ω = 0.524 rad/hr.
∴ Angular velocity of the satellite is 0.524 rad/hr.
Hope it helps.
Answered by
39
In the attachment I have answered this problem.
I have applied basic the relation
Linear velocity
= Angular velocity × radius
to solve this problem.
See the attachment for detailed solution .
I have applied basic the relation
Linear velocity
= Angular velocity × radius
to solve this problem.
See the attachment for detailed solution .
Attachments:
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