Find the angular velocity of particle
the origin
shown at
point P about the origin
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The angular velocity about P is ω
Angle swept about P in time t θ=ωt
Now, from properties of the circle, we know that angle subtended by an arc at the centre is double of the angle subtended anywhere on the circumference.
Hence angle subtended at O in time t is 2θ
Hence angular velocity=ω
o
=
t
2θ
=2ω
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