Question

find the ans of 5 plz

Answer 1

In any quadrilateral sum of internal angles=360

So, A+B+C+D=360

=>A+B=360-160

=>A+B=200

Dividing the above equation by 2,

=>A/2+B/2=100

From the figure,

A/2=PAB

and

B/2=PBA

In triangle APB

PAB+PBA+APB=180

100+APB=180

APB=180-100

APB=80

Answer 2

ᴀ+ʙ+ᴄ+ᴅ=360°
ᴀ+ʙ+100°+60°=360°
ᴀ+ʙ=360°-160°
ᴀ+ʙ=200°
ᴀ+ʙ/2=200°/2
ᴀ+ʙ=100°
ɪɴ ᴛʀɪᴀɴɢʟᴇ ᴀᴩʙ
ᴀɴɢʟᴇ ᴩᴀʙ+ᴀɴɢʟᴇ ᴩʙᴀ+ᴀɴɢʟᴇ ᴩ=180°
100°+ᴀɴɢʟᴇ ᴩ=180°
ᴀɴɢʟᴇ ᴩ= 180°-100°
=80°