Question

Find the Answer 2x*2x-7x+5=0

Answer 1

Given equation

$2x^{2} -7x+5=0$

Solving, we get,

$2x^{2} -7x+5=0$

$\implies 2x^{2} -2x-5x+5=0$

$\implies 2x(x-1)-5(x-1)=0$

$\implies (2x-5)(x-1)=0$

Now,

$2x-5 = 0$

$\implies \boxed{\boxed{\bold{x = \dfrac{5}{2} }}}}}}}}}$

$x-1=0$

$\implies \boxed{\boxed{\bold{x = 1}}}}}}}$

                                                     

Answer 2

Using Splitting Method :

$\implies\tt 2x^2-7x+5=0\\\implies\tt 2x^2-(5-2)x+5=0\\\implies\tt 2x^2-5x-2x+5=0\\\implies\tt x(2x-5)-1(2x-5)=0\\\implies\tt (2x-5)(x-1)==0\\\implies\tt 2x-5=0, x-1=0\\\implies\\\tt x=\frac{5}{2},x=1$

Hence,

$\pink\bf{\underline{\fbox{x=5/2}}}$

$\pink\bf{\underline{\fbox{x= -1 }}}$