find the answer......
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xy = 2 ------(1)
2x + 3y = 8 -----(2)
On cubing both sides, we get
(2x + 3y)^3 = (8)^3
=> 8x^3 + 27y^3 + 3(2x)(3y)(2x + 3y) = 512
=> 8x^3 + 27y^3 + 18xy ( 8) = 512 [ using equation 2]
=> 8x^3 + 27y^3 + 18 × 8 × 2 = 512 [ using equation 1]
=> 8x^3 + 27y^3 + 288 = 512
=> 8x^3 + 27y^3 = 512 - 288
=> 8x^3 + 27y^3 = 224
2x + 3y = 8 -----(2)
On cubing both sides, we get
(2x + 3y)^3 = (8)^3
=> 8x^3 + 27y^3 + 3(2x)(3y)(2x + 3y) = 512
=> 8x^3 + 27y^3 + 18xy ( 8) = 512 [ using equation 2]
=> 8x^3 + 27y^3 + 18 × 8 × 2 = 512 [ using equation 1]
=> 8x^3 + 27y^3 + 288 = 512
=> 8x^3 + 27y^3 = 512 - 288
=> 8x^3 + 27y^3 = 224
Answered by
4
Hi friend!
Consult the attachment for your answer ;)
Hope it helps!
Consult the attachment for your answer ;)
Hope it helps!
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