Question

find the answer and post, plss help

Answer 1

Given

• In ΔABC , BD as line segment
• ∠ABC = 40°
• ∠ACD = 70°

To find

• ∠ACB (x)°
• ∠CAB = (y)°

Solution

• x + 70° = 180°   (Linear Pair)
• x = 180° - 70°
• x = 110°

☯ Measure of x° is 110°

• In ΔABC
• 40° + x° = y°   (Exterior angle property)
• 40° + 110° = y°
• y° = 150°

☯ Measure of y° is 150°