find the answer and post, plss help
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Given
- In ΔABC , BD as line segment
- ∠ABC = 40°
- ∠ACD = 70°
To find
- ∠ACB (x)°
- ∠CAB = (y)°
Solution
- x + 70° = 180° (Linear Pair)
- x = 180° - 70°
- x = 110°
☯ Measure of x° is 110°
- In ΔABC
- 40° + x° = y° (Exterior angle property)
- 40° + 110° = y°
- y° = 150°
☯ Measure of y° is 150°
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