Question

find the answer.


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Answer 1

Answer:

Correct option is B)

Since the capacitors are connected in series so charge flowing through them will be same.

Energy stored in first capacitor of capacitance 0.3μF is given by

E

1

=

2C

1

Q

2

E

1

=

2×0.3

Q

2

Energy stored in second capacitor of capacitance 0.6μF is given by

E

2

=

2C

2

Q

2

E

2

=

2×0.6

Q

2

Now ratio of energy stored by the condensers is given by

E

2

E

1

=

1

2

Solve any question of Electrostatic Potential and Capacitance with:-