Question

find the answer for the question​

Answer 1

• We know that in any triangle the sum of any two sides is greater than the third side.

• In △PQO,PQ+QO>PQ→(1)
• In △SOP,SO+PO>PS→(2)
• In △SOR,SO+OR>RS→(3)o
• In △QOR,QO+OR>QR→(4)

• Adding equations (1) , (2) , (3) & (4) ,

• we get,

• 2(PO+OQ+SO+OR) >PQ+QR+RS+SP
• PQ+QR+RS+SP< 2(PQ+OR+SO+OQ)
• PQ+QR+RS+SP < 2(PR+SQ)

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⇒ ✪ hence proven !!!!!

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