Math, asked by elton2, 1 year ago

find the answer for this question

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Answered by vidhi57
1
let one zero be a so other would be -a.
and both will be equal to 0.
4a^2-(8k^2-40k)a-9=4a^2+(8k^2-40k)a-9
-8k^2+40k=8k^2-40k
16k^2=80k
k=80/16=5
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