find the answer of both the question
Attachments:
Answers
Answered by
0
Solution 1.)
Original speed = 80 km/h
New Speed = 130 km/h
Increase in speed = 130 - 80 = 50 km/h
% of Increase = 50*100/80
= 5*100/8
= 5*25/2
= 125/2
= 62.5 %
Solution 2.)
Original speed = 80 km/h
New Speed = 65 km/h
Decrease in speed = 80 - 65 = 15 km/h
% of Decrease = 15*100/80
= 1500/80
= 150/8
= 18.75 %
Original speed = 80 km/h
New Speed = 130 km/h
Increase in speed = 130 - 80 = 50 km/h
% of Increase = 50*100/80
= 5*100/8
= 5*25/2
= 125/2
= 62.5 %
Solution 2.)
Original speed = 80 km/h
New Speed = 65 km/h
Decrease in speed = 80 - 65 = 15 km/h
% of Decrease = 15*100/80
= 1500/80
= 150/8
= 18.75 %
Answered by
0
Given that the speed of the train = 80km/hr.
(1) Its speed is increased to 130km/hr.
Difference in speed = 130 - 80
= 50.
Percentage of increase in speed = 50/80 * 100
= 62.5%.
(2) Its speed decreases to 65km/hr.
Difference in speed = 80 - 65
= 15.
Percentage of decrease in speed = 15/80 * 100
= 18.75%.
Hope this helps!
(1) Its speed is increased to 130km/hr.
Difference in speed = 130 - 80
= 50.
Percentage of increase in speed = 50/80 * 100
= 62.5%.
(2) Its speed decreases to 65km/hr.
Difference in speed = 80 - 65
= 15.
Percentage of decrease in speed = 15/80 * 100
= 18.75%.
Hope this helps!
Similar questions
Physics,
7 months ago
Computer Science,
7 months ago
Math,
1 year ago
Computer Science,
1 year ago
Environmental Sciences,
1 year ago