find the answer of question no 10 plz
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12harshitab:
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AREA OF SHADED REGION ==> AREA OF SEMICIRCLE - AREA OF BDO SEMI CIRCLE + AREA OF SEMI CIRCLE AB
SO, FIRST AREA OF SEMICIRCLE ==> 1/2πR²
===> 1/2 × 22/7 × (6)²
==> 11/7×36 ==> 396/7 CM²
AREA OF BDO SEMI CIRCLE ==> BO IS DIAMETER OF THIS CIRCLE
==> AB = BC = CO
AND AB+BC+CO = 12
==> AB+AB+AB = 12
==> 3 AB = 12
==> AB = 4
==> AB=BC=CD = 4 CM
SO, BO DIAMETER = 8
AND RADIUS = 8/2 ==> 4
AREA OF BDO SEMI CIRCLE ==> 1/2×22/7×4×4
===> 11/7×16
===> 176/7
NOW, AREA OF SEMI CIRCLE AB
SO, WE KNOW ,AB = 4
SO, RADIUS = 4/2
===>RADIUS = 2
AREA OF SEMICIRCLE AB = 1/2×22/7×2×2
===> 11/7×4
==> 44/7
NOW AREA OF SHADED REGION ==> 396/7 - 176/7 + 44/7
=====> 264/7
ANSWER = 264/7 OR 37.71
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