Math, asked by sarthak1910, 1 year ago

find the answer of question no 10 plz​

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Answers

Answered by 12harshitab
1

Answer:

Step-by-step explanation:

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Answered by thameshwarp9oqwi
1

Answer:

AREA OF SHADED REGION ==> AREA OF SEMICIRCLE - AREA OF BDO SEMI  CIRCLE + AREA OF  SEMI CIRCLE AB

SO, FIRST AREA OF SEMICIRCLE ==> 1/2πR²

===> 1/2 × 22/7 × (6)²

==> 11/7×36 ==> 396/7 CM²

AREA OF BDO SEMI CIRCLE ==> BO IS DIAMETER OF THIS CIRCLE

==> AB = BC = CO

AND AB+BC+CO = 12

==> AB+AB+AB = 12

==> 3 AB = 12

==> AB = 4

==> AB=BC=CD = 4 CM

SO, BO DIAMETER = 8

AND RADIUS = 8/2 ==> 4

AREA OF BDO SEMI CIRCLE ==> 1/2×22/7×4×4

===> 11/7×16

===> 176/7

NOW, AREA OF SEMI CIRCLE AB

SO, WE KNOW ,AB = 4

SO, RADIUS = 4/2

===>RADIUS =  2

AREA OF SEMICIRCLE AB = 1/2×22/7×2×2

===> 11/7×4

==> 44/7

NOW AREA OF SHADED REGION ==> 396/7 - 176/7 + 44/7

=====>   264/7

ANSWER = 264/7 OR 37.71

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