Question

find the answer of the given question​

Answer 1

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YOUR ANSWER:-

Let us first find the diameter of the circle.

we know that triangle ABC is right angled at C .

hence by using Pythagoras theorem we will get,

(AB)^2=(AC)^2+(BC)^2

(AB)^2=(24)^2+(10)^2

(AB)^2=576+100

(AB)^2=676

AB=root (676)=26cm i.e. the diameter of the circle .

hence the radius = 26 ÷2= 13 cm.

now let us find the area of the circle=

$\pi \: r {}^{2}$

$= 3.14 \times {13}^{2}$

$= 530.66 \: cm {}^{2}$

so area of half of the circle ,

=530.66÷2

=265.33cm^2

now let us find the area of the triangle ABC:

$= 1 \div 2(b)(h)$

$= 1 \div 2(10) (24)$

$= 5 \times 24$

$= 120 \: cm {}^{2}$

therefore the area of the shaded area is ,

=area of the semicircle -area of the triangle

=265.33-120

=145.33 cm^2 is your answer...

HOPE IT HELPS YOU....

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