Math, asked by raaj2006, 11 months ago

Find the answer of the question

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Answered by Anonymous
1

Step-by-step explanation:

Given,

Length of the ladder=26m

Distance of the ladder from the wall=7m

In the above situation, A right angled triangle is formed.

Thus here,

Hypotenuse=26m

Base=7m

The distance between the ground and the point where the ladder touches the wall is the perpendicular of the right triangle formed.

We have learnt that, According to Pythagoras theorm,

Hypotenuse^2=Base^2+Perpendicular^2

26^2=7^2+Perpendicular^2

676=49+Perpendicular^2

Perpendicular^2=676-49

Perpendicular^2=627

Perpendicular=√627

Perpendicular=25 m approx

Hence, the distance between the ground and the point where the ladder touches the wall is approximately 25m.

I hope this helps....

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