Question

find the answer of this question ​

Answer 1

$\Huge \color{violet} {\tt {\underline {ANSWER:}}}$

$\large \color{magenta} {\tt {\frac{2x - 3}{3x + 2} = \frac{-2}{3}}}$

$\large \color{violet} {\tt {By~ cross~ multiplication, ~we ~get}}$

$\large \color{magenta} {\tt { 3(2x-3) = -2(3x+2)}}$

$\large \color {magenta} {\tt {\implies 6x - 9 = -6x - 4 }}$

$\large \color{violet} {\tt {By~ transposition~ method,~ we~ get}}$

$\large \color{magenta} {\tt {6x + 6x = -4 + 9}}$

$\large \color{magenta} {\tt {\implies 12x = 5}}$

$\LARGE \color{magenta} {\boxed {\tt {\implies x = \frac{5}{12} }}}$

Answer 2

Step-by-step explanation:

To Solve:-

$\\ \tt{:}\Rrightarrow \dfrac{2x-3}{3x+2}=\dfrac{-2}{3}$

Used Formula:-

• Cross multiplication method

$\boxed{\sf \dfrac{a}{b}=\dfrac{c}{d};\implies ad=bc}$

Solution:-

$\\ \tt{:}\Rrightarrow \dfrac{2x-3}{3x+2}=\dfrac{-2}{3}$

$\\ \tt{:}\Rrightarrow 3(2x-3)=-2(3x+2)$

$\\ \tt{:}\Rrightarrow 6x-9=-6x-4$

$\\ \tt{:}\Rrightarrow 6x+6x=-4+9$

$\\ \tt{:}\Rrightarrow 12x=5$

$\\ \tt{:}\Rrightarrow x=\dfrac{5}{12}$