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For what value of ‘k’, p(x) = x2 – 2kx + 1/2(8k – 8) is divisible by (x – 2)
(a) k = 0
(b) k = for no values of k
c) k∊N
d) k∊R
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Given : p(x) = x² – 2kx + 1/2(8k – 8) is divisible by (x – 2)
To find : for what value of ‘k’
Solution:
p(x) = x² – 2kx + 1/2(8k – 8) is divisible by (x – 2)
x – 2 = 0
=> x = 2
=> p(2) = 0
Hence putting value x = 2
P(2) = 2² – 2k*2 + 1/2(8k – 8) = 0
=> 4 - 4k + 4k - 4 = 0
=> 0
independent of k
so k ∊ R
option d is correct
d) k∊R
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