Math, asked by ajaysingh22072002, 7 months ago

find the answer please
!​

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Answers

Answered by poojacool4455
1

Step-by-step explanation:

 \frac{ \sqrt{5 + 1} }{ \sqrt{5 - 1} }  -  \frac{ \sqrt{5 - 1} }{ \sqrt{5 + 1 } } \\   \frac{ \sqrt{6} }{ \sqrt{4} }  -  \frac{ \sqrt{4} }{ \sqrt{6} }  \\  \frac{ \sqrt{6} }{2}  -  \frac{2}{ \sqrt{6} } \\ taking \: lcm \\  \frac{ \sqrt{(6 \times 6)} - 2 \times 2 }{2 \sqrt{6} }  \\  \frac{6 - 4}{2 \sqrt{6} }  \\   \frac{2}{2 \sqrt{6} }   \\   \\  \frac{1}{ \sqrt{6} } ans

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