Question

find the answer please​

Answer 1

Answer:

9m

Step-by-step explanation:

IN ∆AOB

BY USING PYTHOGORAS THEOREM

8²+z²=10²

z²=100-64

z²=16

z=√16

z=4

BO IS 4m

IN ∆DOC

BY USING PYTHOGORAS THEOREM

12²+y²=13²

y²=169-144

y²=25

y=√25

y=5

OD IS 5m

X=y+z

X=5+4

X=9m

I NAMED THE RIGHT ANGLES AS ANGLE B AND ANGLE D.

Answer 2

Answer:

11cm

Explanation:

Let x be BD such that

AB is perpendicular to BD

CD is perpendicular to BD

Since angle B is 90`

Triangle ABO is a right-angled triangle.

By Pythagoras theorem,

AB² + BO² = AO²

(8)² + BO² = (10)²

64 + BO² = 100

BO² = 36

BO² = 6²

BO = 6 cm

Similarly in triangle COD

CD² + OD² = OC²

(12)² + OD² = (13)²

144 + OD² = 169

OD² = 25

OD = 5 cm

BO + OD = BD

BO + OD = x

6 + 5 = x

x = 11 cm