Question

find the answer please​

Answer 1

$given \: {x}^{2} + \frac{1}{ {x}^{2} }$

${(x + \frac{1}{x})}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } + 2$

${(x + \frac{1}{x})}^{2} = 98 + 2$

${(x + \frac{1}{x})}^{2} =100$

$(x + \frac{1}{x}) = \sqrt{100}$

$x + \frac{1}{x} =10$

${(x + \frac{1}{x})}^{3} = {x}^{3} + \frac{1}{ {x}^{3} } + 3(x + \frac{1}{x} )$

${10}^{3} = {x}^{3} + \frac{1}{ {x}^{3} } + 3 \times 10$

$1000 = {x}^{3} + \frac{1}{ {x}^{3} } + 30$

${x}^{3} + \frac{1}{ {x}^{3} } = 1000 - 30$

${x}^{3} + \frac{1}{ {x}^{3} } = 970$