Question

find the answer... plz fast its urgent​

Answer 1

Answer:

200 ohm and 60 ohm are connected in series

so resistance will be 260 ohm

20 ohm is connected in parallel so

R = 1/260 + 1/20

R = 14/260

R = 18.57

R = v/A

A = 0.21 A as whole

Answer 2

As PQR forms a triangle and if we stretch RQ then 20 ohm resistor will be in series with 60 ohm.

Given :-

R1 = 20 Ohm

R2 = 60 Ohm

R3 = 200 Ohm

V = 4 V

For Resistance in series.

R = R1 + R2

R = 20 + 60

R = 80 ohm

Now, As we know that,

V = IR

I = V/R

I = 4/80

I = 0.05 A

Now,

As it is mili ammeter so current will be measured in mili ampere.

I = 0.05/10-³ mA

I = 0.05 × 10³ mA.