Question

find the answer plz most important

Answer 1

${x}^{2} + 5x - 6 = 0 \\ {x}^{2} + 6x - x - 6 = 0 \\ x(x + 6) - 1(x + 6) = 0 \\ (x - 1)(x + 6) = 0 \\ x = + 1 \: and \: x = - 6$

Answer 2

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SEE,

=> THIS IS THE COMMON FACTORISATION EXAMPLE ......

=> IN SUCH TYPES ONE EQUATION IS GIVEN IN THE QUESTION ......

=> THAT IS OF THE FORM :

$a {x}^{2} + bx + c = 0$


NOW .....

=> TO FIND THE ANSWER U SHOULD DO FOLLOWING STEPS :

1. MULTIPLY A AND C

2. NOW FIND THE PAIR OF NO. WHOSE MULTIPLICATION IS PRODUCT OF A AND C
AND SUM IS B

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${x}^{2} + 5x - 6 = 0$

=> MULTIPLY A AND C

=> A IS 1 IN THIS EQUATION

=> THUS , 1 * -6 = -6

=> NOW THE PRODUCT OF TWO FACTORS IS -6 AND THEIR SUM IS 5

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THOSE TWO NO. ARE 6 AND -1

=> 6 * -1 = -6

=> 6 + ( -1 ) = 5

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NOW DO FOLLOWING STEPS :

=> SPLIT THE MIDDLE TERM :

=> IT SHOULD BE REPLACED BY THE NO. U HAVE FOUND :

=> MEANS THE MIDDLE TERM HERE IS 5X ...

=> REPLACE IT BY 6X AND -1X ....

=> BECAUSE 6X + -1X = 5X

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${x}^{2} + 5x - 6 = 0 \\ \\ {x}^{2} + 6x - 1x - 6 = 0 \\ \\ x(x + 6) - 1(x + 6) = 0 \\ \\ (x - 1)(x + 6) = 0 \\ \\ x - 1 = 0 \: or \: x + 6 = 0 \\ \\ \: so \: x = 1 \: or \: x = - 6$

SO,

=> X = 1 OR X = -6

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