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some students planned a picnic budget for food was Rs 500 but five of them failed to go and thus the cost of food for each member increased by Rs 5 . how many students attend the picnic

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Answered by Anonymous
3

Let x = original number of planned attendees

Let y = cost per person

xy = 500 {equation 1}

(x-5)(y+5) = 500 {equation 2}

From equation 2:

xy + 5x - 5y - 25 = 500

We know xy = 500 so

500 + 5x - 5y - 25 = 500

5x - 5y - 25 = 0

5(x-y-5) = 0

x - y - 5 = 0

From equation 1: y = 500/x

x - 500/x - 5 = 0

Multiply through by x

x2 - 500 - 5x = 0

x2 - 5x - 500 = 0

This can be factored. The factors of -500 that add to -5 are -25(20)

(x-25)(x+20) = 0

x = 25 or x = -20

Discarding the negative, x = 25

This was the original planned numbers for attendance.

The actual number that attended was x-5

20 students attended.

hope it helps......

# Aniket ✌️

Answered by Anonymous
3

Step-by-step explanation:

Let x = original number of planned attendees

Let y = cost per person

 

xy = 500    {equation 1}

(x-5)(y+5) = 500   {equation 2}

 

From equation 2:

xy + 5x - 5y - 25 = 500

We know xy = 500 so

500 + 5x - 5y - 25 = 500

5x - 5y - 25 = 0

5(x-y-5) = 0

x - y - 5 = 0

 

From equation 1:  y = 500/x

 

x - 500/x - 5 = 0

Multiply through by x

x2 - 500 - 5x = 0

x2 - 5x - 500 = 0

This can be factored.  The factors of -500 that add to -5 are -25(20)

(x-25)(x+20) = 0

x = 25 or x = -20

 

Discarding the negative, x = 25

This was the original planned numbers for attendance.

The actual number that attended was x-5

 

20 students attended

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