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Answer:
1,perimeter of triangle =sum of all sides
=12+16+20
=48 cm
2,perimeter of square =4×side
=4×15
=60 cm
3,perimeter of rectangle=2×(L+B)
=2×(8+20)
=2×28
=56 cm
4,perimeter of parallelogram =sum of all parallel sides
=10+12+22
=44 cm
#raja moksh
✯Solution :
✯1. Triangle
Let's solve this !
➝Perimeter of Triangle ∆ = a + b + c
➝ 16 + 20 + 12
➝ 48cm
➝ Area of Triangle ∆ = ab/2
➝ 16×12 / 2
➝ 8×12
➝ 96cm^2
✯2. Square
Let's solve this !
➝ Perimeter of Square ⬛ = 4 × side
➝ 4×15
➝ 60 cm
➝ Area of Square ⬛ = side × side
➝ 15×15
➝ 225 cm^2
✯3. Rectangle
let's solve this too !
➝ Perimeter of Rectangle = 2×( L + B )
➝ 2×(20+8)
➝ 2×(28)
➝ 56 cm
➝ Area of Rectangle = L×B
➝ 20×8
➝ 160 cm^2
✯4. Parallelogram
Let's solve this too !
➝ Perimeter of Parallelogram = 2×(a+b)
➝ 2 × (22+12)
➝ 2×32
➝ 64 cm
➝ Area of Parallelogram = b × h
➝ 22×10
➝ 220 cm^2
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- Formula's used in this Question :
➝Perimeter of Triangle ∆ = a + b + c
➝ Area of Triangle ∆ = ab/2
➝ Perimeter of Square ⬛ = 4 × side
➝ Area of Square ⬛ = side × side
➝ Perimeter of Rectangle = 2×( L + B )
➝ Area of Rectangle = L×B
➝ Perimeter of Parallelogram = 2×(a+b)
➝ Area of Parallelogram = b × h