Question

Find the answer to −1/2(7z+4)+1/5(5z−15)

Answer 1

Answer:

=-1/2(7z+4)+1/5×5(z+3)

=-7z-4+5z+15

=-7z+5z+15-4

=-2z+11

Answer 2

Answer:

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Step-by-step explanation:

We are given : −1/2(7z+4)+1/5(5z−15)

Solution: We have -1/2 in front of parenthesis (7z+4)  and 1/5 in front of parenthesis (5z-15).

That represents multiplication of -1/2 by (7z+4) and multiplication of 1/5 by (5z-15).

So, we need to distribute -1/2 over (7z+4) and 1/5 over (5z-15).

Therefore, −1/2(7z+4)+1/5(5z−15) = -1/2 * 7z -1/2 *4 +1/5*5z + 1/5* -15.

On simplifying this step, we get

-7/2 z - 2 + z -3.

Now, we need to combine like terms.

We have like term of -7/2 z is z and like term of -2 is -3.

Let us add those like terms.

-7/2 z + z:  z could be written as z/1 to add with fraction -7/2 z.

Therefore, -7/2 z + z/1 = -7/2 z + 2z/2     (we took common denomiator here)

= (-7+2)z/2

= -5/2 z.

-2 -3 = -5.

Therefore,

-7/2 z - 2 + z -3 = -7/2 z +z -2-3

= -5/2 z -5.

So, the final answer is  -5/2 z -5.