Question

find the answer to all the bits.
I was really confused while doing this.​

Answer 1

Answer:

construction join p to q

proove AQ=BP

PROOF AD//BC

We join p to q

then,ABPQ Is a parallelogram

AB=PQ

AQ=BP

∆QBA=∆QBP

QB=QB (COMMON)

Angle B=ANGLE A

THEN,AQ=BP IN case 1

Case2

given=PQ=CD

PTOOF=ABCD IS A PARALLELOGRAM

JOIN P YO Q

SO,CDPQ ARE ALSO A PARALLELOGRAM

BECAUSE JOIN P TO Q

PQ//CD

PQ=CD

DQ=CP

PQ=CD PROOVE CASE 2

CASE 3

YOU ARE SEE IN A FITST CASE PROOBE THE

ABPQ IS A PARALLELOGRAM

BECAUSE JOIN P TO Q

SO,ABPQ IS A PARALLELOGRAM PROOVE CASE 3