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Given ax=cq = b and cy =az = d
⇒ ax = b and cq = b
⇒ a = b1/x and c = b1/q
Now consider, cy = az = d → (1)
Now substitute the values of c and a in equation (1), we get
( b1/q)y = (b1/x )z = d
⇒ ( by/q) = (bz/x ) = d
Comparing both the sides, we get
(y/q) = (z/x)
⇒ xy = zq
Hence option (A) is correct.
i hope it will help u
⇒ ax = b and cq = b
⇒ a = b1/x and c = b1/q
Now consider, cy = az = d → (1)
Now substitute the values of c and a in equation (1), we get
( b1/q)y = (b1/x )z = d
⇒ ( by/q) = (bz/x ) = d
Comparing both the sides, we get
(y/q) = (z/x)
⇒ xy = zq
Hence option (A) is correct.
i hope it will help u
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