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1. let two forces be A and B both equal to 5N
since A is perpendicular to B
therefore @(theeta) = 90
Magnitude of resultant R =
whole root under A^2 + B^2 +2AB cos@
putting values of A=B = 5 and @ = 90
we get R =
direction:
let R makes angle ¥ with force B
therefore
tan ¥ = A sin @/B+ A cos @
putting values of A and B = 5 and @ = 90
we get
tan¥ = 1
¥ = 45 degree
therefore
direction of R is 45 degree with force B.
since A is perpendicular to B
therefore @(theeta) = 90
Magnitude of resultant R =
whole root under A^2 + B^2 +2AB cos@
putting values of A=B = 5 and @ = 90
we get R =
direction:
let R makes angle ¥ with force B
therefore
tan ¥ = A sin @/B+ A cos @
putting values of A and B = 5 and @ = 90
we get
tan¥ = 1
¥ = 45 degree
therefore
direction of R is 45 degree with force B.
barsha9:
urgently
centripetal force equals mv^2/r therefore dimensional formula equals MLT^-2
and unit
kg m s^-2
tq
wc
ok
hmm
ya
a body of mass 10kg slides in a horizontal surface by a force of 19.6N. then find out the coefficient of friction.
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