find the AP if the sum and products of the 3rd and 7th terms of an AP are 6 and 8
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given,a+2d+a+6d=6,. (a+2d)(a+6d)=8
2a+8d=6,. a=6-8d/2,. a=3-4d
(3-4d+2d)(3-4d+6d)=8
(3-2d)(3+2d)=8
on solving,. d=+1/2 or -1/2
on putting the value of d we get, a=1 or 5
AP=1,3/2,5/2,7/2...........,. or 1,1/2,0,-1/2.....
2a+8d=6,. a=6-8d/2,. a=3-4d
(3-4d+2d)(3-4d+6d)=8
(3-2d)(3+2d)=8
on solving,. d=+1/2 or -1/2
on putting the value of d we get, a=1 or 5
AP=1,3/2,5/2,7/2...........,. or 1,1/2,0,-1/2.....
koushik43:
thanks bro thank you so much
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