Question

find the ap of tenth term if two first numbers are -5 and 3

Answer 1

First term a1= -5 and second terma2 = 3, so difference d= a2-a1= 8 That's why 10th term = a+9d= -5+9(8)=67

Answer 2

a = -5 , a2 = 3
d = a2 - a = 3- (-5)= 3+5=8
an= a+ (n-1) d
⇒ a10= (-5) + 9( 8)
          = 67
Therefore, the tenth term is 67