Find the ap of whose first term is 4 and common difference is -3
Answers
Answered by
1
Answer:
heya mate there's your answer.
let first term of AP be a1=4
and common difference be d=-3
we know that,
nth term in an AP is,
an=a1+(n-1)d
second term a2= a1+(2-1)d
=4+(1)(-3)
=4-3
a2=1
third term a3=a1+(3-1)d
=4+(2)(-3)
=4-6
a3 =-2
fourth term a4=a1+(4-1)d
=4+(3)(-3)
=4-9
a4=-5
On continuing the process we get the required series.
The required series of AP is 4,1,-2,-5,-8............................,..................
hope it helps you.....
Thank you!!!
Similar questions