Find the AP was 10th is 5 and 18th term is 77
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Given that;
a(10) = 5
a(18) = 77
As we know;
a(10) = a + (n-1) d = a + 9d
A(18) = a + (n-1)d = a + 17d
We can write it as:-
a + 9d = 5 ..(1)
and a + 17d = 77 ..(2)
Subtract both equations to get
a - a + 17d - 9d = 77-5
8d = 72
d = 9
Hence
a = 5 - 9d = 5-81 = -76
Hence, the AP is -76, -67, -58, - 49, -40, -31, -22, -13, -4, 5 etc.
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