Question

find the AP when the sum to n terms is 2n²+6n​

Answer 1

Step-by-step explanation:

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The formula to find the sum of the first n terms of our sequence is n divided by 2 times the sum of twice the beginning term, a, and the product of d, the common difference, and n minus 1. The n stands for the number of terms we are adding together.

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Answer 2

Answer:

Sn=2n^2+6n

When n=1

S1=2(1)^2+6(1)

=2+6

=8

S2=2(2)^2+6(2)

=2(4)+12

=8+12

=20

S3=2(3)^2+6(3)

=2(9)+18

=18+18

=36

According to a formula,

an=Sn-Sn-1

a2=S2-S1

=20-8

=12

a3=S3-S2

=36-20

=16

a4=S4-S3

=2(4)^2+6(4)-36

=32+24-36

=56-36

=20

d=a4-a3=a3-a2

=20-16=16-12

=4

Therefore,the A.P is 8,12,16,20,24.....

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