Question

Find the AP whose 2nd term is 10 and the 6th term exceeds the 4th term by 12

Answer 1

a2=10
a+d=10
d=10-a __________(1)

a6=a4+12
a+5d=a+3d+12
a+5 (10-a)=a+3 (10-a)+12 [Using (1)]
a+50-5a=a+30-3a+12
50-4a=42-2a
50-42=-2a+4a
12=2a
a=12/2
a=6
put a=6 in (1), we get
d=10-6=4
Now A.P. is
a,a+d,a+2d,......
6,10,14,....

Answer 2

Answer:

Step-by-step explanation:

Given :-

2nd term is 10 and the 6th term exceeds the 4th term by 12.

To Find :-

A.P

Solution ;-

⇒ a + 5d = a + 3d  +12

⇒ 5d - 3d = 12

⇒ 2d = 12

⇒ d = 12/2

⇒ d = 6

⇒ a + d = 10

⇒ a + 6 = 10   [Putting d value]

⇒ a = 10 - 6

⇒ a = 4

Now Finding 6th and 4th term

6th Term

= a + 5d

= 4 + 5(6)

= 4 + 30

= 30

4th Term

= a + 3d

= 4 + 3(6)

= 4 + 18

= 22

Hence, the terms of A.P are 4, 10, 16, 22, 28, 34, .......