Find the AP whose 3rd term is -13 and 6th term is 2.
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Given,
a+2d=-13........{1}
And,
a+5d=2........{2}
On subtracting equ 1 and 2 ; we get
d=5
Now putting value of d in {1}, we get;
a=-23
Therefore, required AP is -23,-18,-13....
Hope it helps you.....
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