Find the AP whose 3rd term is 16 and the 7th term is 43
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Answered by
5
a3=16. a7=43
a+2d=16
a+6d=43
-
-4d=-27
d=27/4
a+2d=16
a+2*27/4=16
a=16-27/2
a=32-27/2
a=5/2
a+2d=16
a+6d=43
-
-4d=-27
d=27/4
a+2d=16
a+2*27/4=16
a=16-27/2
a=32-27/2
a=5/2
Answered by
1
By putting this value of (a) in eq. 1
d=27/4
=>A.P-->
5/2,37/4,43,......
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d=27/4
=>A.P-->
5/2,37/4,43,......
If you like my answer
Please mark it as brainliest
And
Be my follower if possible.
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