Question

Find the AP whose first term a=8 and the common difference d=4​

Answer 1

Question :

Find the AP whose first term a=8 and the common difference d=4

Theory :

General term of an AP is given by :

$\bf \: a_{n} = a + (n - 1)d$

where

• a = first term
• d = common difference
• n = no of terms

Solution :

Given : first term , a = 8 and common difference , d = 4

First term = a= 8

Second term = a+ d = = 8+4= 12

third term = a+2d = 8+8= 16

forth term = a+3d = 8+12= 20

Fifth term = a+ 4d = 8+16= 24

Sixth term= a+5d = 8+20= 28

Therefore , Ap series :

8,12,16,20,24,28..........

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More About Arithmetic Progression:

• Sum of n terms of an AP

$\sf \: S_{n} =\dfrac{1}{2}(2a + (n - 1)d)$

• if a,b,c are in Ap then 2b = a+c

Answer 2

Answer:

Refer to the attachment....