Question

find the AP whose nth term is given by 2n -1

Answer 1

nth term of Ap is
tn = 2n-1
now put n=1,2,3…
so AP is
1,3,5,7,9…

Answer 2

The AP whose nth term is 2n-1 is 1,3,5,7,9,...

• The $n^{th}$ term of AP is 2n-1

• The $n^{th}$ term of an AP is given by the formula,

$t_n = a + (n-1)d$

where, a is the first term of AP and d is the common difference of AP

• 2n - 1 = a + nd - d

• Comparing both sides we get,

2n = nd        (Equation 1)

-1 = a - d         (Equation 2)

Using equation 1

d = 2

• Substituting the value of d in equation 2 we get.

a = 1

• Therefore, first term(a) is 1 and common difference(d) is 2.

• The AP becomes 1,3,5,7,9,....