find the AP whose third term is 16 ans seventh term exceeds it's fifth term by 12
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Step-by-step explanation:
nth term = a + (n-1)d
difference between seventh and fifth term
a + 6d - a -4d = 12
2d = 12
d = 6
3rd term ,
a + 2d = 16
a + 2*6 = 16
a = 4
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