find the approximate value of f(2.01) ,where f(x)=4xsquare+5x+2)
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hey here is your answer
4 × (2.01)^2 + 5 (2.01) + 2
4 × 4.0401 + 5 × 2.01 + 2
16.1604 + 10.05 + 2
28.2104
4 × (2.01)^2 + 5 (2.01) + 2
4 × 4.0401 + 5 × 2.01 + 2
16.1604 + 10.05 + 2
28.2104
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