Question

Find the approximate value of f (5.001), where f (x) = x³ – 7x² + 15.

Answer 1

Putting the Value of X in p(x)

p(5.001)=(5.001)^3-7(5.001)^2+15

125.075015001-25.010001+15

115.065014001.

Answer 2

Answer:

f(x)=x^3-7x^2+15

f(5.001)=(5.001)^3-7(5.001)^2+15

=125.06-175.07+15

=140.06-175.07

= -35.01

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