Find the approximation change in the volume V of a cube of side X meters caused by increasing the side by 2% .,
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Cube
CubeSolve for volume
CubeSolve for volumeV=8
CubeSolve for volumeV=8a Edge
CubeSolve for volumeV=8a Edge 2
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Hi
Solution:- given , ∆x = 2% of x = 2x/100 = 0.02x
The volume of the cube V = x³
dv/dx = db/dx = ∆x = 3x²*∆x = 3*x²(0.02x) = 0.06x³
Hence ,the approximate value changes in volume = 0.06x³m³
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