Math, asked by kitt10, 13 days ago

Find the APs in the following missing terms in the boxes :4,11,_,25

Answers

Answered by kp959049
0

Step-by-step explanation:

For this A.P.,

a=2

a

3

=26

We know that, a

n

=a+(n−1)d

a

3

=2+(3−1)d

26=2+2d

24=2d

d=12

a

2

=2+(2−1)12

=14

Therefore, 14 is the missing term.

(ii) For this A.P.,

a

2

=13 and

a

4

=3

We know that, a

n

=a+(n−1)d

a

2

=a+(2−1)d

13=a+d ... (i)

a

4

=a+(4−1)d

3=a+3d... (ii)

On subtracting (i) from (ii), we get,

−10=2d

d=−5

From equation (i), we get,

13=a+(−5)

a=18

a

3

=18+(3−1)(−5)

=18+2(−5)=18−10=8

Therefore, the missing terms are 18 and 8 respectively.

(iii) For this A.P.,

a

1

=5 and

a

4

=9

2

1

We know that, a

n

=a+(n−1)d

a

4

=5+(4−1)d

9

2

1

=5+3d

d=

2

3

a

2

=a+d

a

2

=5+

2

3

a

2

=

2

13

a

3

=a

2

+

2

3

a

3

=8

Answered by Anonymous
1

Answer:

18

Step-by-step explanation:

given :

a=1

d= 11-4= 7

n= 3

a_n = a +(n-1) d

a_n= 4+(3-1) x 7

a_n= 4+2 x7

a_n= 4+14

a_n= 18

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