Math, asked by abenrs3577, 1 year ago

Find the arc length parametrization of the curve r(t) = < cost, sint, 2/3t3/2 >, with the parameter s measuring from (1, 0, 0).

Answers

Answered by gautam96
4
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Answered by ashishks1912
3

Given :

The curve with an equation r(t)= <cost, sint, \frac{2}{3}t>

To find :

The arc length has to be found.

Step-by-step explanation:

  • The arc length can be found by following these steps.
  • It is given that the parameters are (1,0,0).
  • Firstly, the differentiation of r(t) must be found.
  • The differentiation would be

        r'(t)=

  • Then, take the square of the equation.
  • Square of the equation will be,

        |r'(t)|=\sqrt{sin^{2} t+cos^{2} t+1}

  • The formula used is

        sin^{2}t+ cos^{2}t=1

  • Substitute the formula in the above equation.
  • Then, the equation will become

        |r'(t)|=\sqrt{1+1}

  • Sum it all up

        |r'(t)|=\sqrt{2}

  • Now take the integral of the equation,

        r(t)=\sqrt{2}

  • Take the integration with the limits from 0 to 2\pi.
  • Because, the angles will exist from 0 to 2\pi. After 2\pi the values will repeat.
  • After taking the integral, the answer would be

        2\sqrt{2} \pi      

Final answer :

The length of the arc is 2\sqrt{2} \pi units.

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