Find the are of a trapezium whose parallel sides are 15 cm and 23 cm ; where as the non parallel sides are 10 cm and 8cm
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Find the are of a trapezium whose parallel sides are 15 cm and 23 cm ; where as the non parallel sides are 10 cm and 8cm
DC = 15 cm , AB = 23 cm
AD = 10cm and BC = 8 cm
Draw CE parallel to DA which meets AB at point E .
since opposite sides of a quadrilateral AECD are parallel , it is a PARALLELOGRAM !
Also draw CF perpendicular to EB
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Let a = EB = AB - AE = AB - DC = ( 23 - 15 ) cm = 8 cm
b = CE = DA = 10 cm and c = BC = 8cm
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if CE is taken height corresponding to the base BE ,
then :-
Clearly , distance between the parallel sides AB and DC is the length of CF .
AREA OF GIVEN TRAPEZIUM =
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