find the are of a triangle two sides of which are 18 cm and 10 cm and the perimeter is 42 cm
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length of the third side=42-(18+10)=14
Three sides a,b and c of the triangle are 18, 14 and 10 and s=(a+b+c)/2=22
Now use the formula
A=√{(s(s-a)(s-b)(s-c)}
A=√21×3×7×11=22√11
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