Question

Find the are of a triangle whose base is 11 inches and whose height 16 inches

Answer 1

Answer:

88 square inches

Step-by-step explanation:

Area of Triangle = 1/2 x Base x Height

= 1/2 x 11 x 16

= 1/2 x 176

= 88

Answer 2

Question :- Find the are of a triangle whose base is 11 inches and whose height 16 inches ?

Solution :-

Triangle :--- is a plane figure with three straight sides and three angles.

→ Area of ∆ = 1/2 * Base * Height = 1/2* ab* sinC = 1/2 * bc *sinA = 1/2 * ca* sinB = √( s(s-a)(s-b)(s-c) ) [ where s = (a+b+c)/2 ]

given that,

• Base = 11 inches .
• Height = 16 inches .

then,

→ Area of ∆ABC = (1/2) * Base * Height

→ Area of ∆ABC = (1/2) * 11 * 16

→ Area of ∆ABC = 11 * 8

→ Area of ∆ABC = 88 inches² (Ans.)

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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