Question

Find the are of an equilateral triangle whose perimeter is 9root3

Answer 1

Step-by-step explanation:

$perimeter \: \: = 3a {}^{2} = 9 \sqrt{3} \\ a {}^{2} = 3 \sqrt{3} \\ area = \frac{ \sqrt{3} }{4} \times a {}^{2} \\ \\ \frac{ \sqrt{3} }{4} \times 3 \sqrt{3} = \frac{9}{4} anser$