Question

find the are of rectangular plit whise one side is 8.m long and diagonql is of length 17m
$225$
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Answer 1

Correct Question :-

• Find the area of rectangle whose one side is 8m long and diagonal is of length 17m.

Given :-

• Length of the Rectangle = 8m
• One Diagonal of Rectangle = 17m

To Find :-

• What is the Area of Rectangle ?

Solution :-

★ Using Pythagoras Theorem ★

⇛ (Diagonal)² = (Length)² + (Breadth)²

⇛ (17)² = (8)² + (Breadth)²

⇛ 289 = 64 + (Breadth)²

⇛ 289 - 64 = (Breadth)²

⇛ 225 = (Breadth)²

⇛ √225 = Breadth

⇛ 25m = Breadth

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★ Using Area of Rectangle ★

⇛ Area of Rectangle = Length × Breadth

⇛ Area of Rectangle = 8 × 25

⇛ Area of Rectangle = 200m²

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So, Area of Rectangle is 200m²

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More For Knowledge :-

• Area of Square = Side x Side
• Area of Rectangle = Length × Breadth
• Area of Triangle = ½ × base x height
• Area of parallelogram = base x height
• Area of circle = πr²
• Area of Rhombus = ½ × product of its diagonals
• Area of Trapezium = ½ × height × sum of parallel sides
• Area of Polygon = sum of the area of all regions into which it is divided

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