Find the are of right angled PQR, right angled at Q in which PQ = 12 meter and OR= 5 meter
Answers
Answered by
1
In ΔPQR
(PR)2=(PQ)2+(QR)2
(PR)2=(12)2+(5)2
(PR)2=169
PR=13
Now AOBQ is a square
So, QB=x
Then, BR=5−x
Similarly AQ=x
Then AP=12−x
Also, CR=BR
CR=5−x
[∵ Length of tangents drawn from external point are equal]
And, CP=AP=12−x
[∵ Length of tangents drawn from external point are equal]
PR=PC+CR
13=5−x+12−x
2x=4⇒x=2 cm.
pls mark me as BRAINLIEST
Answered by
0
Answer:
k2ks w92nks2omd ms
Step-by-step explanation:
!!!PLS MAKE ME AS BRAINLIES!!!
KSKDMDKKDKDMFJKSKW
O!WM2?!JDJEMWW?IDJHDIE!
Similar questions